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solve $-8x + 1leq17$ and graph the solution $\frac{-8x}{-8}leq\frac{16}…

Question

solve $-8x + 1leq17$ and graph the solution
$\frac{-8x}{-8}leq\frac{16}{-8}$
$xgeq - 2$
solve $2x - 18lt - 4x + 6$ and graph the solution

Explanation:

Step1: Add \(4x\) to both sides

$$2x - 18+4x<-4x + 6+4x$$
$$6x-18 < 6$$

Step2: Add \(18\) to both sides

$$6x-18 + 18<6 + 18$$
$$6x<24$$

Step3: Divide both sides by \(6\)

$$\frac{6x}{6}<\frac{24}{6}$$
$$x < 4$$

Answer:

The solution is \(x < 4\). To graph it, draw an open circle at \(x = 4\) on the number - line (because the inequality is strict, \(x
eq4\)) and shade the part of the number - line to the left of \(4\).