Question

questions 6 & 7
04:59
question 8
06:13

• required 4

1. from the example demonstrated $overline{eg}+overline{gf}congoverline{ef}$ and

$angle egf = 90^{circ}$
$angle egf$ is a right angle
$overline{eg}congoverline{gf}$
$eg = gf$

Explanation:

Based on the geometric construction shown, if $\overline{EG}+\overline{GF}\cong\overline{EF}$, and we assume a perpendicular - bisector construction (common in basic geometric constructions), $\angle EGF = 90^{\circ}$ which means $\angle EGF$ is a right - angle. There is no information in the given problem to suggest that $\overline{EG}\cong\overline{GF}$ or $\overline{EG}=\overline{GF}$.

Answer:

$\angle EGF = 90^{\circ}$
$\angle EGF$ is a Right Angle