Question

question 1 of 10 what is the equation of a circle centered at the origin with radius 13? a. x^2 + y^2 = 13 b. x^3 + y^3 = 169 c. x^2 + y^2 = 169 d. x^3 + y^3 = 13

Explanation:

Step1: Recall circle - equation formula

The standard equation of a circle centered at the origin \((0,0)\) is \(x^{2}+y^{2}=r^{2}\), where \(r\) is the radius of the circle.

Step2: Substitute the given radius

Given \(r = 13\), then \(r^{2}=169\). The equation of the circle is \(x^{2}+y^{2}=169\).

Answer:

C. \(x^{2}+y^{2}=169\)