quadrilateral just has vertices coordinates, ( j(-4,0) ), ( u(1,5) ), ( s(4,2) ), and ( t(-2,-4) ).
find the perimeter of quadrilateral just.
round your answer to the nearest hundredth.
use the keypad to enter the answer in the box provided.
the perimeter of quadrilateral just is units.

Question

Accepted Answer

# Explanation:
## Step1: Calculate the length of $JU$
Use the distance formula $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. For $J(-4,0)$ and $U(1,5)$, $x_1=-4,y_1 = 0,x_2=1,y_2 = 5$.
$$
\begin{align*}
JU&=\sqrt{(1-(-4))^2+(5 - 0)^2}\
&=\sqrt{(1 + 4)^2+5^2}\
&=\sqrt{25 + 25}\
&=\sqrt{50}\approx7.07
\end{align*}
$$
## Step2: Calculate the length of $US$
For $U(1,5)$ and $S(4,2)$, $x_1=1,y_1 = 5,x_2=4,y_2 = 2$.
$$
\begin{align*}
US&=\sqrt{(4 - 1)^2+(2 - 5)^2}\
&=\sqrt{3^2+(-3)^2}\
&=\sqrt{9+9}\
&=\sqrt{18}\approx4.24
\end{align*}
$$
## Step3: Calculate the length of $ST$
For $S(4,2)$ and $T(-2,-4)$, $x_1=4,y_1 = 2,x_2=-2,y_2=-4$.
$$
\begin{align*}
ST&=\sqrt{(-2 - 4)^2+(-4 - 2)^2}\
&=\sqrt{(-6)^2+(-6)^2}\
&=\sqrt{36+36}\
&=\sqrt{72}\approx8.49
\end{align*}
$$
##  Step4: Calculate the  length of $TJ$
For $T(-2,-4)$ and $J(-4,0  )$, $x_1=-2,y_1=-4,x_2=-4,y_2 = 0$.
$$
\begin{align*}
TJ&=\sqrt{(-4-(-2))^2+(0-(-4))^2}\
&=\sqrt{(-4 + 2)^2+(0 + 4)^2}\
&=\sqrt{4 + 16}\
&=\sqrt{20}\approx4.47
\end{align*}
$$
## Step5: Calculate the perimeter $P$
$P=JU + US+ST+TJ$.
$$
\begin{align*}
P&\approx7.07+4.24 + 8.49+4.47\
&=24.27
\end{align*}
$$

# Answer:
$24.27$

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QUESTION IMAGE

Question

Explanation:

Step1: Calculate the length of \(JU\)

Step2: Calculate the length of \(US\)

Step3: Calculate the length of \(ST\)

Step4: Calculate the length of \(TJ\)

Step5: Calculate the perimeter \(P\)

Answer: