Question

(c) problem 20: (first taught in lesson 56)
in rectangle cdgh, find x and y.
after you enter your answer press go.
x = y =

Explanation:

Step1: Use the property of rectangle (opposite sides are equal)

In a rectangle, opposite sides are equal. So we have two equations:

• \(x + 10=x + 7\) (This is wrong, correct is \(x+10 = 3y-3\) and \(2y=x + 7\))

From \(2y=x + 7\), we can express \(x=2y - 7\)
Substitute \(x = 2y-7\) into \(x + 10=3y-3\)
\((2y-7)+10=3y - 3\)

Step2: Solve the equation for \(y\)

Simplify \((2y-7)+10=3y - 3\)
\(2y+3=3y - 3\)
Subtract \(2y\) from both sides: \(3=y - 3\)
Add \(3\) to both sides: \(y=6\)

Step3: Solve for \(x\)

Substitute \(y = 6\) into \(x=2y - 7\)
\(x=2\times6-7\)
\(x=12 - 7\)
\(x = 5\)

Answer:

\(x = 5\), \(y=6\)