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Question
practice problem solve for m∠b
Step1: Apply the Law of Cosines
The Law of Cosines states that \(c^{2}=a^{2}+b^{2}-2ab\cos C\). In \(\triangle ABC\), if we want to find \(\angle B\), let \(a = 15\), \(c=10\), \(b = 12\). Then \(10^{2}=12^{2}+15^{2}-2\times12\times15\times\cos B\).
Step2: Simplify the equation
$$
LATEXBLOCK0
$$
Step3: Find the angle
\(B=\cos^{-1}(0.7472)\approx41.4^{\circ}\)
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\(m\angle B\approx41.4^{\circ}\)