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Question
practice d: (first taught in lesson 53) in parallelogram cfhi, fp = 3y + 2 and pi = y + 4; find y. after you enter your answer press go. y =
Step1: Use the property of parallelogram diagonals
In a parallelogram, the diagonals bisect each other. So \(FP = PI\).
Step2: Set up the equation
Given \(FP = 3y + 2\) and \(PI = y + 4\), we have the equation \(3y+2=y + 4\).
Step3: Solve the equation
Subtract \(y\) from both sides: \(3y - y+2=y - y+ 4\), which simplifies to \(2y+2 = 4\).
Subtract \(2\) from both sides: \(2y+2 - 2=4 - 2\), so \(2y=2\).
Divide both sides by \(2\): \(y=\frac{2}{2}=1\).
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