QUESTION IMAGE
Question
point ( a ) is the image of point ( a ) under a rotation about the origin, ( (0,0) ).
determine the angles of rotation.
choose all answers that apply:
a ( 90^{circ} ) clockwise
b ( 90^{circ} ) counterclockwise
c ( 180^{circ} )
d ( 270^{circ} ) clockwise
e ( 270^{circ} ) counterclockwise
Step1: Recall rotation rules
The rule for a \(90^{\circ}\) clockwise rotation about the origin \((x,y)\to(y, - x)\). The rule for a \(90^{\circ}\) counter - clockwise rotation about the origin \((x,y)\to(-y,x)\). The rule for a \(180^{\circ}\) rotation about the origin \((x,y)\to(-x,-y)\). The rule for a \(270^{\circ}\) clockwise rotation about the origin \((x,y)\to(y, - x)\) (same as \(90^{\circ}\) counter - clockwise). The rule for a \(270^{\circ}\) counter - clockwise rotation about the origin \((x,y)\to(-y,x)\) (same as \(90^{\circ}\) clockwise).
Point \(A=(0,5)\) (assuming \(x = 0,y = 5\)).
Step2: Apply rotation rules
For \(90^{\circ}\) clockwise rotation: \((0,5)\to(5,0)\).
For \(90^{\circ}\) counter - clockwise rotation: \((0,5)\to(- 5,0)\).
For \(180^{\circ}\) rotation: \((0,5)\to(0,-5)\).
For \(270^{\circ}\) clockwise rotation (equivalent to \(90^{\circ}\) counter - clockwise): \((0,5)\to(-5,0)\).
For \(270^{\circ}\) counter - clockwise rotation (equivalent to \(90^{\circ}\) clockwise): \((0,5)\to(5,0)\).
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A. \(90^{\circ}\) clockwise, E. \(270^{\circ}\) counterclockwise