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the perimeter of the triangle below is 45 units. find the length of sid…

Question

the perimeter of the triangle below is 45 units. find the length of side \\( \overline { v x } \\).
write your answer without variables.

Explanation:

Step1: Set up the perimeter equation

The perimeter of a triangle is the sum of its sides. So, \(4z+(3z + 3)+(z + 2)=45\).
Simplify the left - hand side: \((4z+3z+z)+(3 + 2)=45\), which gives \(8z+5 = 45\).

Step2: Solve for \(z\)

Subtract 5 from both sides: \(8z=45 - 5\), so \(8z=40\).
Divide both sides by 8: \(z=\frac{40}{8}=5\).

Step3: Find the length of \(VX\)

Since \(VX = 4z\), substitute \(z = 5\) into the expression. So, \(VX=4\times5\).

Answer:

\(20\)