Question

name:
date:
bell:
homework or (day 1)
directions: determine if segments ab and cd are parallel, perpendicular, or neither

1. ab formed by (-2, 13) and (0, 3)

cd formed by (-5, 0) and (10, 3)

1. ab formed by (3, 7) and (-6, 1)

cd formed by (-6, -5) and (0, -1)

1. ab formed by (-6, 2) and (-2, 4)

cd formed by (-1, 11) and (5, -7)

1. ab formed by (-3, 8) and (2, 3)

cd formed by (-4, 6) and (-8, 2)

1. ab formed by (-8, -1) and (-4, 2)

cd formed by (0, -3) and (12, 6)

1. ab formed by (6, 5) and (3, -1)

cd formed by (2, -5) and (-4, 7)
directions: determine if the given equations are parallel, perpendicular, or neither.

1. 3x + 2y = 6 and y = -\frac{3}{2}x + 5
2. 3y = 4x + 15 and 9x + 12y = 12
3. 8x - 2y = 4 and x + 4y = -12
4. 3x + 2y = 10 and 2x + 3y = -3
5. -4y = -2x + 8 and 3x - 6y = 6
6. y = 8 and x = -1

Explanation:

Step1: Find slope of AB

For points \((-2, 13)\) and \((0, 3)\), slope \(m_{AB}=\frac{3 - 13}{0 - (-2)}=\frac{-10}{2}=-5\)

Step2: Find slope of CD

For points \((-5, 0)\) and \((10, 3)\), slope \(m_{CD}=\frac{3 - 0}{10 - (-5)}=\frac{3}{15}=\frac{1}{5}\)

Step3: Check relationship

Product of slopes: \((-5)\times\frac{1}{5}=-1\), so perpendicular.

Answer:

Perpendicular