Question

the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer. find the perimeter and total area of the polygon shape shown below. all measurements are given in inches. perimeter = 68 inches, area = 192 square inches perimeter = 56 inches, area = 192 square inches perimeter = 56 inches, area = 204 square inches perimeter = 68 inches, area = 240 square inches

Explanation:

Step1: Calculate the perimeter

The perimeter of the polygon is the sum of the lengths of all its outer - sides.
The outer - sides are \(10 + 10+12 + 12+12\).

$$10 + 10+12 + 12+12=56$$

Step2: Calculate the area

The polygon is composed of a square and a triangle.
The area of the square with side \(s = 12\) is \(A_{square}=s^{2}=12\times12 = 144\).
The base of the triangle is equal to the side of the square (\(b = 12\)), and the height \(h = 8\). The area of the triangle is \(A_{triangle}=\frac{1}{2}\times b\times h=\frac{1}{2}\times12\times8=48\).
The total area \(A=A_{square}+A_{triangle}=144 + 48=192\)

Answer:

Perimeter \( = 56\) inches, Area \( = 192\) square inches. So the second option (Perimeter \( = 56\) inches, Area \( = 192\) square inches) is correct.