Question

the mixed numbers in each division problem are rewritten as improper fractions and then as a multiplication problem. complete the table by dragging each missing piece to the correct white rectangle. 1 19/20 15/4 46/5 4/15 39/8 3 21/85 2/5 17/6 35/3 drag these 4 7/8 ÷ 2 1/2 39/8 ÷ 5/2 • 11 2/3 ÷ 3 3/4 35/3 ÷ • 3 1/9

Explanation:

Step1: Recall the rule for dividing fractions

When dividing by a fraction, we multiply by its reciprocal. So, \(\frac{a}{b}\div\frac{c}{d}=\frac{a}{b}\times\frac{d}{c}\)

Step2: For \(4\frac{7}{8}\div2\frac{1}{2}=\frac{39}{8}\div\frac{5}{2}\)

Using the division - to - multiplication rule: \(\frac{39}{8}\div\frac{5}{2}=\frac{39}{8}\times\frac{2}{5}\)
Then, \(\frac{39\times2}{8\times5}=\frac{78}{40}=\frac{39}{20}=1\frac{19}{20}\)

Step3: For \(11\frac{2}{3}\div3\frac{3}{4}\)

First, convert \(3\frac{3}{4}\) to an improper fraction: \(3\frac{3}{4}=\frac{3\times4 + 3}{4}=\frac{15}{4}\)
Using the division - to - multiplication rule: \(\frac{35}{3}\div\frac{15}{4}=\frac{35}{3}\times\frac{4}{15}\)
\(\frac{35\times4}{3\times15}=\frac{140}{45}=\frac{28}{9}=3\frac{1}{9}\)

Answer:

For \(4\frac{7}{8}\div2\frac{1}{2}\):

• Rewrite as multiplication: \(\frac{39}{8}\cdot\frac{2}{5}\)
• Solution: \(1\frac{19}{20}\)

For \(11\frac{2}{3}\div3\frac{3}{4}\):

• Rewrite as improper fractions: \(\frac{35}{3}\div\frac{15}{4}\)
• Rewrite as multiplication: \(\frac{35}{3}\cdot\frac{4}{15}\)