Question

mia was given the triangle below to solve for x.

step a:
\\( \cos ( 1 9. 4 ) =. 9 4 3 \\)
step b:
\\( x = a ^ { 2 } + b ^ { 2 } - 2 a b \cos c \\)
step c:
\\( x = 8. 0 6 ^ { 2 } + 1 0 ^ { 2 } - 2 cdot 8. 0 6 cdot 1 0 cdot 0. 9 4 3 \\)
step d:
\\( x = 1 2. 9 2 \\)
what was the first step she made an error or did she solve for x correctly?

Explanation:

Step1: Recall the Law of Cosines formula

The Law of Cosines formula is \(x^{2}=a^{2}+b^{2}-2ab\cos C\), not \(x = a^{2}+b^{2}-2ab\cos C\). Mia made a mistake in Step B.

Answer:

Mia made an error in Step B.