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Question
meredith likes to walk to work. her office and home are both on pioneer avenue, but she sometimes takes different streets for exercise. pythagorean theorem: ( a^{2}+b^{2}=c^{2} ) ( mathrm{km}= ) kilometer about how far is merediths office from her home using pioneer avenue? ( 1.5 mathrm{~km} ) ( 2.0 mathrm{~km} ) ( 2.5 mathrm{~km} ) ( 3.0 mathrm{~km} )
Step1: Apply Pythagorean Theorem
$$a^{2}+b^{2}=c^{2}$$
Here, \(a = 2\) km, \(b=1.5\) km.
Step2: Substitute values
$$2^{2}+1.5^{2}=c^{2}$$
$$4 + 2.25=c^{2}$$
$$c^{2}=6.25$$
Step3: Solve for \(c\)
$$c=\sqrt{6.25}$$
$$c = 2.5$$
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C. \(2.5\) km