Question

the measure of the vertex angle of an isosceles triangle is 58°. what is the measure of one of the triangles base angles? enter deg after any value that is in degrees.

Explanation:

Step1: Recall the sum of angles in a triangle

The sum of angles in a triangle is \(180^{\circ}\).

Step2: Let the measure of each base angle be \(x\)

In an isosceles triangle, the two base angles are equal. The vertex angle is \(58^{\circ}\). So, \(x + x+58^{\circ}=180^{\circ}\), which simplifies to \(2x=180^{\circ}- 58^{\circ}\).

Step3: Solve for \(x\)

\(2x = 122^{\circ}\), then \(x=\frac{122^{\circ}}{2}=61^{\circ}\)

Answer:

\(61\) deg