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m∠hjk = □°

Question

m∠hjk = □°

Explanation:

Step1: Use the Hypotenuse - Leg (HL) Congruence Theorem

Since \(HJ = HJ\) (common side), \(JH = 90\) (given), \(JI\perp IH\), \(JK\perp KH\), and \(IH = KH=90\), by the HL Congruence Theorem, \(\triangle IJH\cong\triangle KJH\).

Step2: Use the property of congruent triangles

If \(\triangle IJH\cong\triangle KJH\), then \(\angle IJH=\angle KJH\).

Step3: Calculate \(\angle HJK\)

Given \(\angle IJH = 67^{\circ}\), and \(\angle IJK = 90^{\circ}\) (right - angle). Let \(m\angle HJK=x\). Then \(x = 90^{\circ}-67^{\circ}\)

Answer:

\(23\)