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Question
if \\( \triangle fgh \sim \triangle kjh \\), find \\( fh \\).
Step1: Use the property of similar triangles
Since \(\triangle FGH\sim\triangle KJH\), the ratios of corresponding sides are equal. So, \(\frac{FH}{KH}=\frac{GH}{JH}\). Substituting the given values, we get \(\frac{4x - 25}{52}=\frac{x + 8}{32}\).
Step2: Cross - multiply
Cross - multiplying gives \(32(4x-25)=52(x + 8)\).
Expanding both sides: \(128x-800 = 52x+416\).
Step3: Solve for \(x\)
Subtract \(52x\) from both sides: \(128x-52x-800=52x - 52x+416\), which simplifies to \(76x-800 = 416\).
Add \(800\) to both sides: \(76x-800 + 800=416+800\), so \(76x=1216\).
Divide both sides by \(76\): \(x=\frac{1216}{76}=16\).
Step4: Find \(FH\)
Substitute \(x = 16\) into \(FH=4x-25\). So \(FH=4\times16-25\).
Calculate: \(FH = 64-25=39\).
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