Question

1. $m\angle aeb = 37^{\circ}$, what is $m\angle ced$?

$m\angle ced =$______$^{\circ}$

Explanation:

Step1: Use the property of a straight - line angle

We know that \(\angle AEB+\angle BEC+\angle CED = 180^{\circ}\). Since \(\angle BEC = 90^{\circ}\) (right - angle).
So, \(37^{\circ}+90^{\circ}+\angle CED=180^{\circ}\).

Step2: Solve for \(\angle CED\)

\(\angle CED=180^{\circ}-(37^{\circ} + 90^{\circ})\).
\(\angle CED=180^{\circ}-127^{\circ}\).
\(\angle CED = 53^{\circ}\).

Answer:

\(53\)