line segment ef is shown on a coordinate grid. the segment is rotated 90° clockwise about the origin to create line segment ef. what is the length of line segment ef?

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Accepted Answer

# Explanation:
## Step1: Find the length of $EF$
Use the distance formula $d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. For points $E(2,1)$ and $F(6,1)$, $x_1 = 2,y_1=1,x_2 = 6,y_2 = 1$.
$$
\begin{align*}
d&=\sqrt{(6 - 2)^2+(1 - 1)^2}\
&=\sqrt{4^2+0^2}\
&=\sqrt{16}\
&=4
\end{align*}
$$
## Step2: Use the property of rotation
Rotation is a rigid transformation. Rigid transformations (such as rotation) preserve the length of line - segments. So $E'F'=EF$

# Answer:
$4$

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Question

Explanation:

Step1: Find the length of \(EF\)

Step2: Use the property of rotation

Answer: