QUESTION IMAGE
Question
lesson 6 - 2
- complete the proof.
given: ( xy = 6 ), ( xz = 14 )
prove: ( yz = 8 )
| statements | reasons |
|---|---|
| 2. ( xy+yz = xz ) | 2. |
| 3. ( 6 + yz = 14 ) | 3. |
| 4. ( yz = 8 ) | 4. |
- based on the given information in item 9, can you conclude that ( y ) is the midpoint of ( xz )? explain your reasoning.
Problem 9:
Step1: Identify Reason for Statement 1
The first statement is just restating the given information, so the reason is "Given".
Step2: Identify Reason for Statement 2
The equation \(XY + YZ=XZ\) comes from the Segment Addition Postulate, which states that if a point \(Y\) is on segment \(XZ\), then \(XY + YZ = XZ\). So the reason is "Segment Addition Postulate".
Step3: Identify Reason for Statement 3
We substitute \(XY = 6\) (from Statement 1) into the equation from Statement 2, so the reason is "Substitution Property of Equality".
Step4: Identify Reason for Statement 4
To solve \(6+YZ = 14\) for \(YZ\), we subtract 6 from both sides (Subtraction Property of Equality), so \(YZ=14 - 6=8\). The reason is "Subtraction Property of Equality".
A midpoint of a segment divides the segment into two equal - length segments. For \(Y\) to be the midpoint of \(XZ\), we need \(XY=YZ\). We know that \(XY = 6\) and \(YZ = 8\). Since \(6
eq8\), \(Y\) does not divide \(XZ\) into two equal parts.
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| Statements | Reasons |
|---|---|
| 2. \(XY+YZ = XZ\) | 2. Segment Addition Postulate |
| 3. \(6 + YZ=14\) | 3. Substitution Property of Equality |
| 4. \(YZ = 8\) | 4. Subtraction Property of Equality |