Question

1. δklm, ∠k = 90°, m = 12.4 m, l = 8.8 cm

Explanation:

Assuming the problem is to find the length of the hypotenuse \( KM \) (wait, no, the triangle is \( \triangle KLM \) with right angle at \( K \), so sides \( KL = 12.4 \) (let's assume units are consistent, maybe a typo, let's take cm), \( KM = 8.8 \) cm, and we need to find the hypotenuse \( LM \) using the Pythagorean theorem.

Step1: Recall Pythagorean theorem

For a right triangle with legs \( a \) and \( b \), hypotenuse \( c \), \( c = \sqrt{a^2 + b^2} \). Here, \( a = 12.4 \) cm, \( b = 8.8 \) cm.

Step2: Calculate \( a^2 + b^2 \)

\( a^2 = 12.4^2 = 153.76 \), \( b^2 = 8.8^2 = 77.44 \). Sum: \( 153.76 + 77.44 = 231.2 \)

Step3: Take square root

\( c = \sqrt{231.2} \approx 15.205 \) cm (rounded to three decimal places)

Answer:

The length of the hypotenuse \( LM \) is approximately \( 15.21 \) cm (or more precise \( \sqrt{231.2} \approx 15.205 \) cm). If the problem was to find area, area \( = \frac{1}{2} \times 12.4 \times 8.8 = 54.56 \) cm². Assuming hypotenuse calculation, the answer is approximately \( 15.21 \) cm.