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△jkl has vertices with the coordinates j(4,5), k(7,9), and l(11,6). fin…

Question

△jkl has vertices with the coordinates j(4,5), k(7,9), and l(11,6).
find the approximate perimeter of △jkl using the distance formula. round your answer to the nearest hundredth.
use the keypad to enter the answer in the box.
the perimeter of △jkl is □ units.

Explanation:

Step1: Calculate the length of \(JK\)

The distance formula is \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\). For points \(J(4,5)\) and \(K(7,9)\), \(x_1 = 4,y_1 = 5,x_2 = 7,y_2 = 9\).

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Step2: Calculate the length of \(KL\)

For points \(K(7,9)\) and \(L(11,6)\), \(x_1 = 7,y_1 = 9,x_2 = 11,y_2 = 6\).

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Step3: Calculate the length of \(LJ\)

For points \(L(11,6)\) and \(J(4,5)\), \(x_1 = 11,y_1 = 6,x_2 = 4,y_2 = 5\).

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Step4: Calculate the perimeter

Perimeter \(P=JK + KL+LJ\). Substitute \(JK = 5\), \(KL = 5\), and \(LJ\approx7.07\) into the formula.

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Answer:

\(17.07\)