Question

jazlyn owns an indoor trampoline park. the scale drawing shows a new trampoline she wants to purchase for her facility. the scale is shown in the drawing (1 in. : 3 ft; l = 4 in., w = 2 in.). what number can you multiply each length in the scale drawing by to find the actual length? what are the actual length and width of the trampoline? actual length = 12 ft actual width = 6 ft what is the actual area of the trampoline? 8 ft² 24 ft² 36 ft² 72 ft²

Explanation:

Step1: Recall the formula for the area of a rectangle

The area \( A \) of a rectangle is given by the formula \( A = \text{length} \times \text{width} \).

Step2: Identify the actual length and width

From the problem, the actual length of the trampoline is \( 12 \) ft and the actual width is \( 6 \) ft.

Step3: Calculate the area

Substitute the values of length and width into the area formula:
\( A = 12 \, \text{ft} \times 6 \, \text{ft} \)
\( A = 72 \, \text{ft}^2 \)? Wait, no, wait. Wait, no, let's check again. Wait, the length is 12 ft and width is 6 ft? Wait, no, wait the scale is 1 in : 3 ft. The drawing length is 4 in, so actual length is \( 4 \times 3 = 12 \) ft. Drawing width is 2 in, so actual width is \( 2 \times 3 = 6 \) ft. Then area is \( 12 \times 6 = 72 \)? Wait, but let's check the options. Wait, the options are 8, 24, 36, 72. Wait, maybe I made a mistake. Wait, no, 126 is 72. Wait, but let's confirm. Wait, length is 12 ft, width is 6 ft. Area is length times width, so 126=72. So the actual area is 72 square feet.

Wait, but let me check again. Wait, the scale is 1 inch to 3 feet. The drawing length is 4 inches, so actual length is 43=12 ft. Drawing width is 2 inches, so actual width is 23=6 ft. Then area is 12*6=72 ft². So the correct option is 72 ft².

Answer:

72 ft² (corresponding to the option with 72 ft²)