Question

if $\triangle rst$ is isosceles, what is the measure of $angle s$?

Explanation:

Step1: Use the property of isosceles triangle

In an isosceles triangle \( \triangle RST\), if \(RS = TS\), then \( \angle R=\angle T = 41^{\circ}\) (base - angles of an isosceles triangle are equal).

Step2: Use the angle - sum property of a triangle

The sum of the interior angles of a triangle is \(180^{\circ}\). Let \( \angle S=x\). Then \(x + 41^{\circ}+41^{\circ}=180^{\circ}\).

Step3: Solve for \(x\)

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Answer:

\(98^{\circ}\)