QUESTION IMAGE
Question
- how many radians are there in a quarter of a circle?
a. $\pi/6$ radians
b. $\pi/3$ radians
c. $\pi/8$ radians
d. $\pi/2$ radians
- what is the center of a circle represented by $(x - 4)^2 + (y + 7)^2 = 81$?
a. $(-4, -7)$
b. $(4, -7)$
c. $(4, 7)$
d. $(-4, 7)$
- how do you rewrite the equation $x^2 + y^2 + 6x - 8y - 11 = 0$ in standard form?
a. $(x - 3)^2 + (y + 4)^2 = 36$
b. $(x + 3)^2 + (y - 4)^2 = 36$
c. $(x - 3)^2 + (y - 4)^2 = 36$
d. $(x + 3)^2 + (y + 4)^2 = 36$
- which of the following describes the circumcenter in a right triangle?
a. it coincides with the centroid
b. it divides the triangle into three smaller triangles of equal area
c. it is the lowest point of the triangle
d. it is located at the midpoint of the hypotenuse
- what is true about the circumcenter of a triangle?
a. it is the same as the incenter
b. it is equidistant from all vertices
c. it is always inside the triangle
d. it is always on the hypotenuse
- if a central angle measures $2\pi/5$ radians in a circle with radius 5 cm, what is the arc length?
a. $5\pi$ cm
b. $2\pi$ cm
c. $3\pi$ cm
d. $\pi$ cm
- which of the following points are used in constructing the incircle?
a. incenter
b. tangent
c. circumcenter
d. centroid
Question 8
Step1: Recall the total radians in a circle
A full circle is \(2\pi\) radians.
Step2: Calculate a quarter of a circle
A quarter means \(\frac{1}{4}\) of the total. So, \(\frac{1}{4} \times 2\pi=\frac{\pi}{2}\) radians.
Step1: Recall the standard circle equation
The standard form of a circle's equation is \((x - h)^2+(y - k)^2 = r^2\), where \((h,k)\) is the center.
Step2: Identify \(h\) and \(k\) from the given equation
For the equation \((x - 4)^2+(y + 7)^2 = 81\), we can rewrite \(y + 7\) as \(y-(-7)\). So, \(h = 4\) and \(k=-7\).
Step1: Start with the given equation
The equation is \(x^{2}+y^{2}+6x - 8y-11 = 0\).
Step2: Group \(x\) and \(y\) terms
Group the \(x\) terms and \(y\) terms: \((x^{2}+6x)+(y^{2}-8y)=11\).
Step3: Complete the square for \(x\) terms
For \(x^{2}+6x\), take half of 6 (which is 3) and square it: \(3^{2}=9\). Add 9 to both sides.
Step4: Complete the square for \(y\) terms
For \(y^{2}-8y\), take half of - 8 (which is - 4) and square it: \((-4)^{2}=16\). Add 16 to both sides.
Step5: Rewrite the equation
We get \((x^{2}+6x + 9)+(y^{2}-8y + 16)=11 + 9+16\). Which simplifies to \((x + 3)^{2}+(y - 4)^{2}=36\) (since \(x^{2}+6x + 9=(x + 3)^{2}\) and \(y^{2}-8y + 16=(y - 4)^{2}\) and \(11 + 9+16 = 36\)).
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d. \(\pi/2\) radians