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greek architects considered a rectangle whose length was approximately …

Question

greek architects considered a rectangle whose length was approximately 1.6 times its width to be the most visually appealing. write an equation for the length and width of a rectangle constructed in this manner if the sum of the length and width is 156 ft. (let w represent the width of the rectangle.)

Explanation:

Step1: Express length in terms of width

Given that the length \( L = 1.6W \) (where \( W \) is the width).

Step2: Use the sum - length and width relationship

The sum of the length and width is \( L+W=156 \). Substitute \( L = 1.6W \) into the equation: \( 1.6W+W = 156 \).

Answer:

\( 1.6W+W = 156 \)