Question

graph the image of $\triangle tuv$ after a dilation with a scale factor of 3, centered at the origin.

Explanation:

Step1: Identify original coordinates

From graph: $T(-3,-1)$, $U(3,-1)$, $V(-3,2)$

Step2: Apply dilation rule

Multiply each coordinate by scale factor 3:
$T' = (-3×3, -1×3) = (-9,-3)$
$U' = (3×3, -1×3) = (9,-3)$
$V' = (-3×3, 2×3) = (-9,6)$

Step3: Plot new triangle

Graph $T'(-9,-3)$, $U'(9,-3)$, $V'(-9,6)$ and connect.

Answer:

The image triangle has vertices at $(-9,-3)$, $(9,-3)$, and $(-9,6)$ (plot these points to form the dilated triangle).