Question

graph the image of l(1, -8) after a reflection over the y-axis.

Explanation:

Step1: Recall reflection over y - axis rule

The rule for reflecting a point \((x,y)\) over the \(y\) - axis is \((x,y)\to(-x,y)\).

Step2: Apply the rule to point \(L(1, - 8)\)

For the point \(L(1,-8)\), when we reflect it over the \(y\) - axis, we change the sign of the \(x\) - coordinate. So, if \(x = 1\) and \(y=-8\), the new \(x\) - coordinate is \(-x=-1\) and the \(y\) - coordinate remains the same (\(y = - 8\)). So the image of \(L(1,-8)\) after reflection over the \(y\) - axis is the point \((-1,-8)\). To graph this point, we find the location on the coordinate plane where \(x=-1\) and \(y = - 8\) (1 unit to the left of the origin on the \(x\) - axis and 8 units down on the \(y\) - axis).

Answer:

The image of \(L(1,-8)\) after reflection over the \(y\) - axis is the point \((-1,-8)\) (and it should be graphed at the coordinates \((-1,-8)\) on the given grid).