QUESTION IMAGE
Question
- graph all 3 lines on the same grid. state the slope, rise, run and y - intercept. label the lines.
①: ( y = x + 2 )
slope: ( m = )
rise =
run =
y - intercept: ( b = )
②: ( y = x - 4 )
slope: ( m = )
rise =
run =
y - intercept: ( b = )
③: ( y = x )
slope: ( m = )
rise =
run =
y - intercept: ( b = )
(there is a coordinate grid and a pencil in the image, and some hand - written answers on the original paper)
To solve the problem of graphing the three lines \( y = x + 2 \), \( y = x - 4 \), and \( y = x \), we analyze each line using the slope - intercept form \( y=mx + b \), where \( m \) is the slope and \( b \) is the y - intercept. The slope \( m=\frac{\text{rise}}{\text{run}} \).
For Line 1: \( y=x + 2 \)
- Step 1: Identify the slope (\( m \)) and y - intercept (\( b \))
- In the slope - intercept form \( y=mx + b \), for the equation \( y=x + 2 \), we can rewrite it as \( y = 1x+2 \). So, the slope \( m = 1\) and the y - intercept \( b = 2 \).
- Since the slope \( m=\frac{\text{rise}}{\text{run}}=1=\frac{1}{1} \), the rise (change in \( y \)) is \( 1 \) and the run (change in \( x \)) is \( 1 \).
- Step 2: Graph the line
- Start by plotting the y - intercept. The y - intercept is \( 2 \), so we plot the point \( (0,2) \) on the y - axis.
- Then, use the slope to find the next point. Since the rise is \( 1 \) and the run is \( 1 \), from the point \( (0,2) \), we move up \( 1 \) unit and then to the right \( 1 \) unit to get the point \( (1,3) \). We can continue this process to plot more points and then draw a straight line through the plotted points.
For Line 2: \( y=x - 4 \)
- Step 1: Identify the slope (\( m \)) and y - intercept (\( b \))
- In the slope - intercept form \( y=mx + b \), for the equation \( y=x - 4 \), we can rewrite it as \( y = 1x-4 \). So, the slope \( m = 1\) and the y - intercept \( b=- 4 \).
- Since the slope \( m=\frac{\text{rise}}{\text{run}} = 1=\frac{1}{1}\), the rise is \( 1 \) and the run is \( 1 \).
- Step 2: Graph the line
- Start by plotting the y - intercept. The y - intercept is \( - 4 \), so we plot the point \( (0,-4) \) on the y - axis.
- Then, use the slope to find the next point. Since the rise is \( 1 \) and the run is \( 1 \), from the point \( (0,-4) \), we move up \( 1 \) unit and then to the right \( 1 \) unit to get the point \( (1,-3) \). We can continue this process to plot more points and then draw a straight line through the plotted points.
For Line 3: \( y=x \)
- Step 1: Identify the slope (\( m \)) and y - intercept (\( b \))
- In the slope - intercept form \( y=mx + b \), for the equation \( y=x \), we can rewrite it as \( y = 1x+0 \). So, the slope \( m = 1\) and the y - intercept \( b = 0 \).
- Since the slope \( m=\frac{\text{rise}}{\text{run}}=1=\frac{1}{1}\), the rise is \( 1 \) and the run is \( 1 \).
- Step 2: Graph the line
- Start by plotting the y - intercept. The y - intercept is \( 0 \), so we plot the point \( (0,0) \) (the origin).
- Then, use the slope to find the next point. Since the rise is \( 1 \) and the run is \( 1 \), from the point \( (0,0) \), we move up \( 1 \) unit and then to the right \( 1 \) unit to get the point \( (1,1) \). We can continue this process to plot more points and then draw a straight line through the plotted points.
Summary of the properties of the lines:
| Line | Equation | Slope (\( m \)) | Rise | Run | Y - intercept (\( b \)) |
|---|---|---|---|---|---|
| 2 | \( y=x - 4 \) | \( 1 \) | \( 1 \) | \( 1 \) | \( - 4 \) |
| 3 | \( y=x \) | \( 1 \) | \( 1 \) | \( 1 \) | \( 0 \) |
When graphing, all three lines are parallel (since they have the same slope \( m = 1\)) and are shifted vertically based on their y - intercepts.
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To solve the problem of graphing the three lines \( y = x + 2 \), \( y = x - 4 \), and \( y = x \), we analyze each line using the slope - intercept form \( y=mx + b \), where \( m \) is the slope and \( b \) is the y - intercept. The slope \( m=\frac{\text{rise}}{\text{run}} \).
For Line 1: \( y=x + 2 \)
- Step 1: Identify the slope (\( m \)) and y - intercept (\( b \))
- In the slope - intercept form \( y=mx + b \), for the equation \( y=x + 2 \), we can rewrite it as \( y = 1x+2 \). So, the slope \( m = 1\) and the y - intercept \( b = 2 \).
- Since the slope \( m=\frac{\text{rise}}{\text{run}}=1=\frac{1}{1} \), the rise (change in \( y \)) is \( 1 \) and the run (change in \( x \)) is \( 1 \).
- Step 2: Graph the line
- Start by plotting the y - intercept. The y - intercept is \( 2 \), so we plot the point \( (0,2) \) on the y - axis.
- Then, use the slope to find the next point. Since the rise is \( 1 \) and the run is \( 1 \), from the point \( (0,2) \), we move up \( 1 \) unit and then to the right \( 1 \) unit to get the point \( (1,3) \). We can continue this process to plot more points and then draw a straight line through the plotted points.
For Line 2: \( y=x - 4 \)
- Step 1: Identify the slope (\( m \)) and y - intercept (\( b \))
- In the slope - intercept form \( y=mx + b \), for the equation \( y=x - 4 \), we can rewrite it as \( y = 1x-4 \). So, the slope \( m = 1\) and the y - intercept \( b=- 4 \).
- Since the slope \( m=\frac{\text{rise}}{\text{run}} = 1=\frac{1}{1}\), the rise is \( 1 \) and the run is \( 1 \).
- Step 2: Graph the line
- Start by plotting the y - intercept. The y - intercept is \( - 4 \), so we plot the point \( (0,-4) \) on the y - axis.
- Then, use the slope to find the next point. Since the rise is \( 1 \) and the run is \( 1 \), from the point \( (0,-4) \), we move up \( 1 \) unit and then to the right \( 1 \) unit to get the point \( (1,-3) \). We can continue this process to plot more points and then draw a straight line through the plotted points.
For Line 3: \( y=x \)
- Step 1: Identify the slope (\( m \)) and y - intercept (\( b \))
- In the slope - intercept form \( y=mx + b \), for the equation \( y=x \), we can rewrite it as \( y = 1x+0 \). So, the slope \( m = 1\) and the y - intercept \( b = 0 \).
- Since the slope \( m=\frac{\text{rise}}{\text{run}}=1=\frac{1}{1}\), the rise is \( 1 \) and the run is \( 1 \).
- Step 2: Graph the line
- Start by plotting the y - intercept. The y - intercept is \( 0 \), so we plot the point \( (0,0) \) (the origin).
- Then, use the slope to find the next point. Since the rise is \( 1 \) and the run is \( 1 \), from the point \( (0,0) \), we move up \( 1 \) unit and then to the right \( 1 \) unit to get the point \( (1,1) \). We can continue this process to plot more points and then draw a straight line through the plotted points.
Summary of the properties of the lines:
| Line | Equation | Slope (\( m \)) | Rise | Run | Y - intercept (\( b \)) |
|---|---|---|---|---|---|
| 2 | \( y=x - 4 \) | \( 1 \) | \( 1 \) | \( 1 \) | \( - 4 \) |
| 3 | \( y=x \) | \( 1 \) | \( 1 \) | \( 1 \) | \( 0 \) |
When graphing, all three lines are parallel (since they have the same slope \( m = 1\)) and are shifted vertically based on their y - intercepts.