Question

m/j grade 7 math_pr_0303_(1901205040cjt3fy26)
topic 4: readiness assessment
1 ft
5 ft
2 ft
10 square feet
18 square feet
28 square feet
32 square feet

Explanation:

Step1: Calculate the dimensions of the outer rectangle

The length of the outer rectangle is \(5 + 1+1=7\) ft (adding 1 ft on top and bottom of the inner rectangle's length of 5 ft). The width of the outer rectangle is \(2 + 1+1 = 4\) ft (adding 1 ft on left and right of the inner rectangle's width of 2 ft).

Step2: Calculate the area of the outer rectangle

The area of a rectangle is \(A = \text{length}\times\text{width}\). So, \(A_{outer}=7\times4 = 28\) square - feet.

Step3: Calculate the area of the inner rectangle

The area of the inner rectangle with length \(l = 5\) ft and width \(w = 2\) ft is \(A_{inner}=5\times2=10\) square - feet.

Step4: Calculate the area of the shaded region (assuming we want the area between the outer and inner rectangles)

The area of the region between the two rectangles is \(A=A_{outer}-A_{inner}\). But if the problem is asking for the area of the outer rectangle (since the options have 28), and there is no indication of shading (a common problem - type in such multiple - choice with rectangles within rectangles where the outer rectangle's area is calculated as above).

Answer:

28 square feet