Question

given right triangle mnl, what is the value of cos(m)? - o $\frac{3}{5}$ o $\frac{3}{4}$ o $\frac{4}{5}$ o $\frac{5}{3}$

Explanation:

Step1: Identify right triangle parts

Right-angled at N, hypotenuse ML=25, NL=15.

Step2: Calculate adjacent side MN

Using Pythagoras: $MN^2 = ML^2 - NL^2 = 25^2 - 15^2 = 625 - 225 = 400$, so $MN=20$.

Step3: Compute cos(M)

$\cos(M) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{MN}{ML} = \frac{20}{25} = \frac{4}{5}$.

Answer:

C. $\frac{4}{5}$