Question

given rhombus qrst below, su = 11. if uq = 2x - 3, solve for x.

Explanation:

Step1: Use property of rhombus diagonals

In a rhombus, the diagonals are perpendicular bisectors of each other. So \(UQ = SU\).

Step2: Set up equation and solve for \(x\)

Since \(UQ = SU\), we have \(2x - 3=11\).
Add \(3\) to both sides: \(2x=11 + 3\), so \(2x=14\).
Divide both sides by \(2\): \(x=\frac{14}{2}\).

Answer:

\(x = 7\)