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given rectangle klmn below, lo = 24. if ko = 3x + 6, solve for x.

Question

given rectangle klmn below, lo = 24. if ko = 3x + 6, solve for x.

Explanation:

Step1: Use property of rectangle diagonals

In a rectangle, diagonals are equal and bisect each other. So \( KO = LO \).

Step2: Set up equation

Since \( KO = 3x + 6 \) and \( LO = 24 \), we have \( 3x + 6 = 24 \).

Step3: Solve for \( x \)

Subtract 6 from both sides: \( 3x = 24 - 6 \), so \( 3x = 18 \).
Divide both sides by 3: \( x=\frac{18}{3} \).

Answer:

\( x = 6 \)