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Question
given: \\( \overleftrightarrow { a c } \parallel \overleftrightarrow { b d } \\) \\( \overleftrightarrow { a b } \parallel \overleftrightarrow { c d } \\), and \\( \overleftrightarrow { a c } \perp \overleftrightarrow { c d } \\).
prove: \\( \angle p c q \\) is complementary to \\( \angle a b c \\).
what is the missing step in the given proof?
\\( \bigcirc \\) a. \\( \angle p q c \\) and \\( \angle a c p \\) are supplementary by the linear pair theorem.
\\( \bigcirc \\) b. for parallel lines cut by a transversal, corresponding angles are congruent, so \\( \angle a c b \cong \angle p c q \\).
\\( \bigcirc \\) c. \\( \angle o c p \cong \angle b c d \\) by the vertical angles theorem.
\\( \bigcirc \\) d. for parallel lines cut by a transversal, corresponding angles are congruent, so \\( \angle o c p \cong \angle a b c \\).
\\( \bigcirc \\) e. for parallel lines cut by a transversal, corresponding angles are congruent, so \\( \angle o c a \cong \angle c b d \\).
Step1: Analyze each option
- Option A: \(\angle PQC\) and \(\angle ACP\) are not relevant to proving \(\angle PCQ\) is complementary to \(\angle ABC\).
- Option B: \(\angle ACB\) and \(\angle PCQ\) are not directly related to the given parallel lines and the angle - complement relationship.
- Option C: \(\angle OCP\) and \(\angle BCD\) have no connection to the proof of \(\angle PCQ\) and \(\angle ABC\) being complementary.
- Option D: Since \(\overleftrightarrow{AC}\parallel\overleftrightarrow{BD}\) (given) and they are cut by transversal \(\overleftrightarrow{AB}\), by the Corresponding Angles Theorem, \(\angle OCA\cong\angle CBD\). This is not relevant to the proof of \(\angle PCQ\) and \(\angle ABC\) being complementary.
- Option E: Because \(\overleftrightarrow{AB}\parallel\overleftrightarrow{CD}\) (given) and they are cut by transversal \(\overleftrightarrow{BC}\), by the Corresponding Angles Theorem, \(\angle OCP\cong\angle ABC\). Also, since \(\overleftrightarrow{AC}\perp\overleftrightarrow{CD}\), \(\angle ACD = 90^{\circ}\). And \(\angle ACD=\angle OCP+\angle PCQ\) (angle - addition postulate). So \(\angle PCQ\) is complementary to \(\angle OCP\). Since \(\angle OCP\cong\angle ABC\), \(\angle PCQ\) is complementary to \(\angle ABC\).
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C. \(\angle OCP\cong\angle BCD\) by the Vertical Angles Theorem.