Question

given the following vectors, calculate $-9mathbf{u}$.
$mathbf{u}=langle-9,1
angle,mathbf{v}=langle1,1
angle$

Explanation:

Step1: Multiply each component of vector \(u\) by \(-9\)

Given \(u=\langle -9,1
angle\), to find \(-9u\), we use the scalar - vector multiplication rule. If \(u = \langle a,b
angle\) and \(k\) is a scalar, then \(ku=\langle ka,kb
angle\). Here \(k=-9\), \(a = - 9\), and \(b = 1\).

For the first component: \((-9)\times(-9)\)
For the second component: \((-9)\times1\)

Step2: Calculate each component

The first component: \((-9)\times(-9)=81\)
The second component: \((-9)\times1=-9\)

Answer:

\(\langle81,-9
angle\)