Question

give the center and radius of the circle described by the equation and graph the equation. use the graph to identify the domain and range.

$(x + 5)^2+(y - 6)^2 = 4$

the center is $(-5,6)$.
(type an ordered pair. simplify your answer.)

the radius is $\square$.
(type an integer or a simplified fraction.)

Explanation:

Step1: Recall the standard form of a circle equation

The standard form of a circle equation is \((x - h)^2+(y - k)^2=r^2\), where \((h,k)\) is the center and \(r\) is the radius.

Step2: Compare with the given equation

Given \((x + 5)^2+(y - 6)^2 = 4\), we can rewrite it as \((x-(-5))^2+(y - 6)^2=2^2\).

Answer:

The radius is \(2\).