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fountain what is the perimeter of this block? = what is the area of thi…

Question

fountain
what is the perimeter of this block?
=
what is the area of this block?
=

Explanation:

Step1: Recall the formula for the perimeter of a rectangle

The perimeter formula of a rectangle is \(P = 2\times(\text{length}+\text{width})\). Here, the length \(l = 10\) yd and the width \(w=x + 4\) yd.

$$P=2\times(10)+2\times(x + 4)$$

Step2: Simplify the perimeter expression

$$ LATEXBLOCK0 $$

Step3: Recall the formula for the area of a rectangle

The area formula of a rectangle is \(A=\text{length}\times\text{width}\). Substitute \(l = 10\) yd and \(w=x + 4\) yd.

$$A = 10\times(x + 4)$$

Step4: Simplify the area expression

$$ LATEXBLOCK1 $$

Answer:

For the perimeter: \(2\times10+2\times(x + 4)=2x + 28\)
For the area: \(10\times(x + 4)=10x + 40\)