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Question
find \\(\tan\theta\\), where \\(\theta\\) is the angle shown. give an exact value, not a decimal approximation. the right triangle has hypotenuse 25, one leg 7, and angle \\(\theta\\) at the vertex with the leg of length 7 and the hypotenuse. \\(\tan\theta = \square\\)
Step1: Recall tangent definition
In a right triangle, $\tan\theta = \frac{\text{opposite}}{\text{adjacent}}$. First, find the opposite side using Pythagoras. Let opposite side be $y$, hypotenuse $25$, adjacent $7$. So $y = \sqrt{25^2 - 7^2} = \sqrt{625 - 49} = \sqrt{576} = 24$.
Step2: Calculate $\tan\theta$
Now, $\tan\theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{24}{7}$.
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$\frac{24}{7}$