Question

find the value of sin j rounded to the nearest hundredth, if necessary. answer attempt 1 out of 3 sin j =

Explanation:

Step1: Recall the definition of sine in a right - triangle

In a right - triangle, \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\). For \(\angle J\), the side opposite to \(\angle J\) is \(KL = \sqrt{6}\), and the hypotenuse is \(JL=4\).

Step2: Calculate \(\sin J\)

\(\sin J=\frac{KL}{JL}\)
Substitute \(KL = \sqrt{6}\) and \(JL = 4\) into the formula: \(\sin J=\frac{\sqrt{6}}{4}\)
Calculate \(\frac{\sqrt{6}}{4}\approx\frac{2.45}{4}=0.61\)

Answer:

\(0.61\)