Question

find: \cos a\
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(right triangle with right angle at the bottom left, vertical leg labeled 10 (side b), horizontal leg labeled 24 (side a), hypotenuse labeled 26)\
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\the figure is not drawn to scale\\
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answer\
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\boxed{\frac{10}{24}} \quad \boxed{\frac{10}{26}} \quad \boxed{\frac{24}{10}} \quad \boxed{\frac{24}{26}}

Explanation:

Step1: Recall cosine definition

In a right triangle, $\cos\theta = \frac{\text{adjacent}}{\text{hypotenuse}}$ for an angle $\theta$.

Step2: Identify sides for $\angle A$

For $\angle A$, adjacent side is 24, hypotenuse is 26.

Step3: Calculate $\cos A$

$\cos A = \frac{24}{26}$

Answer:

$\frac{24}{26}$ (corresponding to the fourth option: $\frac{24}{26}$)