QUESTION IMAGE
Question
find the measure of each numbered angle.
m∠1 = \boxed{}, m∠2 = \boxed{}, m∠3 = \boxed{}, m∠4 = \boxed{}
Step1: Find \( m\angle1 \)
The triangle with \( \angle1 \) is a right triangle (one angle is \( 90^\circ \)) and has a \( 70^\circ \) angle. The sum of angles in a triangle is \( 180^\circ \). So, \( m\angle1 = 180^\circ - 90^\circ - 70^\circ = 20^\circ \).
Step2: Find \( m\angle2 \)
\( \angle2 \) and the \( 70^\circ \) angle are vertical angles? Wait, no, looking at the diagram, the angle adjacent to \( 35^\circ \) and \( \angle3 \) and \( \angle2 \): Wait, actually, the angle with \( 35^\circ \), \( \angle3 \), and the right angle? Wait, no, let's re-examine. The angle at the bottom left: \( 35^\circ + \angle3 + \) (right angle?) Wait, no, the vertical angle to the \( 70^\circ \) angle is equal to \( \angle2 \)? Wait, no, maybe \( \angle2 \) is equal to \( 70^\circ \) because they are vertical angles? Wait, no, let's see: the triangle with \( \angle1 \) has a \( 70^\circ \) angle, and the angle opposite to that (vertical angle) is \( \angle2 \)? Wait, maybe \( \angle2 = 70^\circ \)? Wait, no, let's do step by step.
Wait, the angle marked \( 70^\circ \) and \( \angle2 \): are they vertical angles? If so, \( m\angle2 = 70^\circ \). Wait, maybe. Alternatively, the triangle with \( 35^\circ \), \( \angle3 \), and the right angle? Wait, the bottom angle: \( 35^\circ + \angle3 + 90^\circ - \angle2 \)? No, maybe better to find \( \angle3 \) first.
Step3: Find \( m\angle3 \)
The angle at the bottom: \( 35^\circ + \angle3 + \) (the right angle? Wait, the total angle at the bottom is \( 90^\circ \)? Wait, the diagram has a right angle at the bottom left? Wait, the figure has a right angle on the left side (vertical) and bottom (horizontal). So, \( 35^\circ + \angle3 + \) (the angle equal to \( \angle2 \))? No, wait, the sum of angles around a point? No, let's look at the triangle with \( \angle4 \). Wait, \( \angle4 \) is in a triangle with \( \angle3 \) and the angle equal to \( \angle1 \)? Wait, no, let's start over.
Wait, \( m\angle1 = 20^\circ \) (from step1). Now, \( \angle4 \) should be equal to \( \angle1 \) because they are alternate interior angles? Wait, maybe the two triangles are similar? Or \( \angle4 = m\angle1 = 20^\circ \). Let's check:
If \( m\angle1 = 20^\circ \), then \( m\angle4 = 20^\circ \) (since they are corresponding angles or alternate interior angles).
Now, for \( \angle3 \): the angle at the bottom: \( 35^\circ + \angle3 + 90^\circ - \angle2 \)? No, wait, the vertical line and horizontal line form a right angle (90°). So, \( 35^\circ + \angle3 + \) (the angle between \( \angle3 \) and the horizontal) = 90°? Wait, no, the angle with \( 35^\circ \), \( \angle3 \), and the angle equal to \( \angle2 \): Wait, maybe \( \angle2 = 70^\circ \), then \( 35^\circ + \angle3 + 70^\circ = 90^\circ \)? No, that can't be. Wait, I think I made a mistake.
Wait, let's use the fact that the sum of angles in a triangle is \( 180^\circ \), and vertical angles are equal.
- \( m\angle1 \): triangle with \( 90^\circ \) and \( 70^\circ \): \( 180 - 90 - 70 = 20^\circ \). So \( m\angle1 = 20^\circ \).
- \( \angle2 \) and the \( 70^\circ \) angle: vertical angles, so \( m\angle2 = 70^\circ \).
- Now, the angle at the bottom: \( 35^\circ + \angle3 + \angle2 = 90^\circ \) (since it's a right angle). So \( 35 + \angle3 + 70 = 90 \)? No, that would be \( \angle3 = 90 - 35 - 70 = -15 \), which is impossible. So my mistake here.
Wait, maybe the right angle is at the top left, and the bottom left angle: \( 35^\circ + \angle3 + \) (the angle equal to \( \angle1 \))? No, let's look at the vertical angle of \( \angle2 \): maybe…
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\( m\angle1 = \boxed{20^\circ} \), \( m\angle2 = \boxed{70^\circ} \), \( m\angle3 = \boxed{35^\circ} \), \( m\angle4 = \boxed{20^\circ} \)