Question

find the magnitudes of the horizontal and vertical components of v, if α is the direction angle of v from the horizontal. α = 65°10, |v| = 11.6 the horizontal component of v is □. (round to the nearest tenth as needed.)

Explanation:

Step1: Use horizontal component formula

Horizontal component $v_x = |v|\cos\alpha$

Step2: Substitute values

$v_x = 11.6 \times \cos(65^\circ)$

Step3: Calculate cosine value

$\cos(65^\circ) \approx 0.4226$

Step4: Compute and round

$v_x \approx 11.6 \times 0.4226 \approx 4.9$

Answer:

4.9