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QUESTION IMAGE

find the lengths of the missing sides in the triangle. write your answe…

Question

find the lengths of the missing sides in the triangle. write your answers as integers or as decimals rounded to the nearest tenth.
not drawn to scale
$x = 12.7, y = 9$
$x = 7.8, y = 6.4$
$x = 6.4, y = 7.8$
$x = 9, y = 12.7$

Explanation:

Step1: Identify the triangle type

This is a right - angled triangle with one angle \(45^{\circ}\), so it is a \(45 - 45-90\) triangle. In a \(45 - 45-90\) triangle, the legs are equal. But wait, no, if one of the non - right angles is \(45^{\circ}\), and the other non - right angle is \(180-(90 + 45)=45^{\circ}\). Wait, no, no, actually, if we use trigonometric ratios. Let's assume the side opposite to \(45^{\circ}\) is \(y = 9\) (one of the legs).

Step2: Use trigonometric ratios to find \(x\) (hypotenuse)

We know that \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\) and \(\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}\). For \(\theta = 45^{\circ}\), \(\sin45^{\circ}=\cos45^{\circ}=\frac{\sqrt{2}}{2}\approx0.707\). If \(y = 9\) (opposite side to \(45^{\circ}\)), and using \(\sin45^{\circ}=\frac{y}{x}\), then \(x=\frac{y}{\sin45^{\circ}}\). Substitute \(y = 9\) into the formula: \(x=\frac{9}{\sin45^{\circ}}=\frac{9}{0.707}\approx12.7\).

Answer:

A. \(x = 12.7,y = 9\)