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find the equation in standard form for the circle with center (0, 7) an…

Question

find the equation in standard form for the circle with center (0, 7) and radius 9.

Explanation:

Step1: Recall circle - standard form

The standard - form equation of a circle is $(x - h)^2+(y - k)^2=r^2$, where $(h,k)$ is the center of the circle and $r$ is the radius.

Step2: Identify values of $h$, $k$, and $r$

Given that the center is $(0,7)$, so $h = 0$, $k = 7$, and the radius $r = 9$.

Step3: Substitute values into the formula

Substitute $h = 0$, $k = 7$, and $r = 9$ into $(x - h)^2+(y - k)^2=r^2$. We get $(x - 0)^2+(y - 7)^2=9^2$.

Step4: Simplify the equation

$(x - 0)^2=x^2$ and $9^2 = 81$, so the equation is $x^2+(y - 7)^2=81$.

Answer:

$x^2+(y - 7)^2=81$