QUESTION IMAGE
Question
- find the base angles of the figure below.
50°
130°
65°
25°
Step1: Use the property of isosceles triangle
In an isosceles triangle \(ABC\) (\(AB = AC\)), \(\angle B=\angle C\). The sum of interior angles of a triangle is \(180^{\circ}\), so \(\angle A+\angle B+\angle C = 180^{\circ}\).
Step2: Substitute and calculate
Given \(\angle A = 130^{\circ}\), then \(130^{\circ}+\angle B+\angle C=180^{\circ}\). Since \(\angle B=\angle C\), let \(\angle B = \angle C=x\). So \(130 + 2x=180\). Solve for \(x\):
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\(25^{\circ}\)