Question

find the area of this trapezoid. 6 cm 4 cm 8 cm area of a trapezoid $a = \frac { 1 } { 2 } h ( b _ { 1 } + b _ { 2 } )$ $a = ? cm ^ { 2 }$

Explanation:

Step1: Identify the values of \(h\), \(b_1\), and \(b_2\)

From the problem, \(h = 4\mathrm{cm}\), \(b_1=6\mathrm{cm}\), \(b_2 = 8\mathrm{cm}\)

Step2: Substitute the values into the formula

Substitute into \(A=\frac{1}{2}h(b_1 + b_2)\)

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Step3: Calculate the result

First, \(\frac{1}{2}\times4 = 2\), then \(2\times14=28\)

Answer:

\(28\mathrm{cm}^2\)