Question

find the area of this trapezoid. 8 m 3 m 12 m area of a trapezoid $a = \frac { 1 } { 2 } h ( b _ { 1 } + b _ { 2 } )$ $a = \square m ^ { 2 }$

Explanation:

Step1: Substitute the values into the formula

Given \(h = 3\), \(b_1=8\), \(b_2 = 12\), substitute into \(A=\frac{1}{2}h(b_1 + b_2)\).
\(A=\frac{1}{2}\times3\times(8 + 12)\)

Step2: Calculate the sum of the bases

First, calculate \(8+12\).
\(8 + 12=20\)
So the formula becomes \(A=\frac{1}{2}\times3\times20\)

Step3: Calculate the product

\(\frac{1}{2}\times3\times20=\frac{1}{2}\times60\)

Step4: Final calculation

\(\frac{1}{2}\times60 = 30\)

Answer:

\(30\)