Question

find the area of this trapezoid. 10 m 6 m 8 m area of a trapezoid $a = \frac { 1 } { 2 } h ( b _ { 1 } + b _ { 2 } )$ $a = \square m ^ { 2 }$

Explanation:

Step1: Identify the values of \(b_1\), \(b_2\), and \(h\)

\(b_1 = 10\) m, \(b_2 = 8\) m, \(h = 6\) m

Step2: Substitute the values into the formula \(A=\frac{1}{2}h(b_1 + b_2)\)

\(A=\frac{1}{2}\times6\times(10 + 8)\)

Step3: Simplify the expression

First, calculate \(10+8 = 18\). Then, \(\frac{1}{2}\times6 = 3\). Finally, \(3\times18=54\)

Answer:

\(54\)