Question

find the area of this irregular shape. a = ? ft² find the area of rectangle 2. 16ft²

Explanation:

Step1: Identify dimensions of Rectangle 2

Rectangle 2 has a width of 2 ft and a height of 4 ft (from the diagram: the vertical segment is 4 ft, and the horizontal segment is 2 ft).

Step2: Calculate area of Rectangle 2

The formula for the area of a rectangle is \( A = \text{length} \times \text{width} \). Substituting the values, we get \( A = 2 \, \text{ft} \times 4 \, \text{ft} \).

Step3: Compute the product

\( 2 \times 4 = 8 \), so the area of Rectangle 2 is \( 8 \, \text{ft}^2 \). But wait, we also have the top and bottom rectangles. Wait, let's re - evaluate the entire shape. The top rectangle: length 8 ft, width 2 ft, area \( 8\times2 = 16 \, \text{ft}^2 \). The bottom rectangle: length 8 ft, width 2 ft, area \( 8\times2 = 16 \, \text{ft}^2 \). The middle rectangle: length 4 ft, width 2 ft, area \( 4\times2 = 8 \, \text{ft}^2 \). Now, sum all these areas: \( 16 + 8+16=40 \, \text{ft}^2 \). Wait, maybe my initial step was wrong. Let's look at the shape again. The irregular shape can be divided into three rectangles: top (8ft x 2ft), middle (2ft x 4ft), and bottom (8ft x 2ft). So area of top: \( 8\times2 = 16 \), middle: \( 2\times4 = 8 \), bottom: \( 8\times2 = 16 \). Total area: \( 16 + 8+16 = 40 \).

Answer:

\( 40 \)