QUESTION IMAGE
Question
find angle 3.
61
51
29
Step1: Find angle 1
The sum of angles in a triangle is \(180^{\circ}\).
\(\angle1 = 180^{\circ}-68^{\circ}-61^{\circ}=51^{\circ}\)
Step2: Use vertical angles
\(\angle1\) and \(\angle2\) are vertical angles, so \(\angle2=\angle1 = 51^{\circ}\)
Step3: Find angle 3
In the right - angled triangle with \(\angle2\), \(\angle3=180^{\circ}-90^{\circ}-\angle2\)
Substitute \(\angle2 = 51^{\circ}\), \(\angle3=180^{\circ}-90^{\circ}-51^{\circ}=39^{\circ}\)
Wait, there is a mistake above. Let's correct it.
Step1: Use vertical angles
The angle of \(61^{\circ}\) and the non - right angle adjacent to \(\angle2\) are vertical angles.
In the right - angled triangle where \(\angle3\) is located, we know that the sum of angles in a triangle is \(180^{\circ}\)
\(\angle3=180^{\circ}-90^{\circ}-61^{\circ}=29^{\circ}\)
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\(29^{\circ}\)